If `f(x) {-x-pi/2,xle-pi/2 and -cosx,-pi/2 lt xle0 and x-1,0 lt x le1 and lnx,x gt 1` then- - YouTube
=1&line2=\mathrm{Solution:\:}x=%CF%80n%2B\frac{3%CF%80}{4} "tan(x-pi/2)=1")
tan(x-pi/2)=1
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Wallis product - Wikipedia
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=\frac{1}{2}&line2=\mathrm{Solution:\:}x=\frac{2%CF%80}{3}%2B2%CF%80n,x=2%CF%80n%2B2%CF%80 "cos(x-pi/3)= 1/2")
cos(x-pi/3)= 1/2
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![lim_[x- gtpi/2]cosx/[x-pi/2]` - YouTube](https://i.ytimg.com/vi/_GCXQ4Jqzp8/maxresdefault.jpg "lim_[x- gtpi/2]cosx/[x-pi/2]` - YouTube")
lim_[x- gtpi/2]cosx/[x-pi/2]` - YouTube
![The range of f(x) = sin\ pi/2 [x] is, (Here [x] denotes greatest integ](https://d10lpgp6xz60nq.cloudfront.net/ss/web/208221.jpg "The range of f(x) = sin\ pi/2 [x] is, (Here [x] denotes greatest integ")
The range of f(x) = sin\ pi/2 [x] is, (Here [x] denotes greatest integ
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f(x) = {{:((k cos x)/(pi-2x ), " if " , x ne (pi)/(2)),(3, "if" , x =
Ex 12.1, 22 - lim x->pi/2 tan 2x/x-pi/2 - Chapter 13 Class 11
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If cos x = -3/5 and pi/2 < x < pi , then sin x/2 = ?
