![For tha function `f(x)=(pi-x)(cosx)/(|sinx|); x!=pi and f(pi)=1,` which of the following state - YouTube For tha function `f(x)=(pi-x)(cosx)/(|sinx|); x!=pi and f(pi)=1,` which of the following state - YouTube](https://i.ytimg.com/vi/DdxaRwiZNvY/maxresdefault.jpg)
For tha function `f(x)=(pi-x)(cosx)/(|sinx|); x!=pi and f(pi)=1,` which of the following state - YouTube
![Consider the function f(x) = x sin pi/x, for x>0 0, for x = 0 . Then, the number of points in (0,1) where the derivative f'(x) vanishes is Consider the function f(x) = x sin pi/x, for x>0 0, for x = 0 . Then, the number of points in (0,1) where the derivative f'(x) vanishes is](https://haygot.s3.amazonaws.com/questions/1553048_121246_ans_1a21ea3929b041efa356547e6dbebd40.jpg)
Consider the function f(x) = x sin pi/x, for x>0 0, for x = 0 . Then, the number of points in (0,1) where the derivative f'(x) vanishes is
![SOLVED: f(x) =-1 when -pI <= X < 0 f(x) = 1 when 0 <= X <= pI f(x) IS periodic function with period = 2*pI. Find a0,an, bn and the corresponding Fourier Series: SOLVED: f(x) =-1 when -pI <= X < 0 f(x) = 1 when 0 <= X <= pI f(x) IS periodic function with period = 2*pI. Find a0,an, bn and the corresponding Fourier Series:](https://cdn.numerade.com/ask_images/a91423a0284246cc83fbc628e947e815.jpg)
SOLVED: f(x) =-1 when -pI <= X < 0 f(x) = 1 when 0 <= X <= pI f(x) IS periodic function with period = 2*pI. Find a0,an, bn and the corresponding Fourier Series:
![If `f(x) = cos [pi]x + cos [pi x]`, where `[y]` is the greatest integer function of y then `f - YouTube If `f(x) = cos [pi]x + cos [pi x]`, where `[y]` is the greatest integer function of y then `f - YouTube](https://i.ytimg.com/vi/Ibx1ycLyoGE/maxresdefault.jpg)
If `f(x) = cos [pi]x + cos [pi x]`, where `[y]` is the greatest integer function of y then `f - YouTube
![Use Fourier series of $f(x)=x(\pi-|x|)$ in $(-\pi,\pi)$ to compute the series $\sum_{n=1}^{\infty}\frac{(-1)^{n+1}}{(2n-1)^3}.$ - Mathematics Stack Exchange Use Fourier series of $f(x)=x(\pi-|x|)$ in $(-\pi,\pi)$ to compute the series $\sum_{n=1}^{\infty}\frac{(-1)^{n+1}}{(2n-1)^3}.$ - Mathematics Stack Exchange](https://i.stack.imgur.com/lAKpd.jpg)
Use Fourier series of $f(x)=x(\pi-|x|)$ in $(-\pi,\pi)$ to compute the series $\sum_{n=1}^{\infty}\frac{(-1)^{n+1}}{(2n-1)^3}.$ - Mathematics Stack Exchange
![calculus - Why isn't $f(x) = x\cos\frac{\pi}{x}$ differentiable at $x=0$, and how do we foresee it? - Mathematics Stack Exchange calculus - Why isn't $f(x) = x\cos\frac{\pi}{x}$ differentiable at $x=0$, and how do we foresee it? - Mathematics Stack Exchange](https://i.stack.imgur.com/ZLLUu.png)